Callin out to IT nerds, this one fell a sleep in class :(

Discussion in 'Non Technical' started by JETzx, Oct 31, 2006.

  1. JETzx

    JETzx X-FACTOR

    Hows it going guys, would you be kind enough to help me out with this question.

    "
    Briefly explain the following snort output:

    [**] SCAN Proxy (8080) attempt [**]
    10/19-16:05:17.158329 10.1.1.254:55415 -> 10.1.1.67:8080
    TCP TTL:64 TOS:0x0 ID:39399 IpLen:20 DgmLen:60 DF
    ******S* Seq: 0x6E8722C1 Ack: 0x0 Win: 0x16D0 TcpLen: 40
    TCP Options (5) => MSS: 1460 SackOK TS: 1206303526 0 NOP WS: 2
    =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+"

    Many thanks in advance
    Cheers
    pat
     
  2. artin

    artin ...there is no spoon

    hmm this ones a bit too advanced for me...what is this output from?? like what u do to get this output??
     
  3. Eastern Eye

    Eastern Eye !!! MOST WANTED !!!

  4. black baz

    black baz black 'n blue Bazemy

    definitely an output from way toooo much snort ..!!

    ..methinks .. umm, must do something about posting pics, one day ..:eek: :eek: snort, snort, snort ... :p :p :p ;) ;) ;) :eek: :eek: :eek: :D :D :D



     
  5. bigbaz

    bigbaz New Member

    At least you know your Sack is OK
     
  6. black baz

    black baz black 'n blue Bazemy

    bigbaz .. not necessarily so .. that could mean that it

    is OK to go ahead with the sacking ... ..lol..lol..!!:eek: :eek: :eek: :p :p ;) ;)


     
  7. bigbaz

    bigbaz New Member

    OH yeah well i suppose, if thats the case i would suggest a plenum pull and some chrome badges:D :cool: , wont help with the sacking but you will have some sweet bling and a bit more reliability
     
  8. loud'n'proud

    loud'n'proud Challenge Accepted

    easy mate

    the answer is 42....

    whats the question again?
     
  9. Claymen

    Claymen Active Member

    hmmmm well...

    Being snort is used for intrusion detection my guess is that its picked up someone scanning port 8080 which is commonly used for web proxies. In other words looks like someone is trying to find open proxies and happened to scan your IP. They were probably scanning an entire IP range.

    Sorry I cant be any more helpful but I havent used snort in a while.

     
  10. JETzx

    JETzx X-FACTOR

    Thanks claymen and others for help
    Cheers
    Pat

     
  11. vbevan

    vbevan Active Member

    Don't use snort but this looks like an internal query. 10.1.1.254 is sending a ping to 10.1.1.67. Since .254 is using port 55415, and I think 10.1.1.254 is usually one of the addresses used by a server, I'd say the server was sending ..67 a hello or maybe some data on port 8080. The rest of the crap I know bits and pieces of but it isn't as important...

    EDIT: just rechecked, also, sometimes 8080 is used by some trojans to send data through. Make sure you have a virus-checker running just in case. (though I assume if your playing with port scanners you know enough to have an anti-virus up)
     
    Last edited: Nov 1, 2006
  12. XTREME ZX

    XTREME ZX ZED Xtremist

    Pat

    Its a little difficult to understand the switches specified. But if it was somone port scanning externally chances are that your machine would not have responded to a 8080 port request. If you are running a proxy and you hae a predefined port of 8080 then i yes you may have been pinged.

    I would run a finger on your machine (finger print) to see if there was anything left behind in the recent probe... (geeze this sounds like sexual story HHAHAHAHAH) There are tools out there that can do this for you... Just google it. Or you can try this site
    http://www.snort.org/archive-2-3029.html

    I would look at changing the proxy port to a .pac file this will remove the dependency on the port traffic and rather route traffic through a config.. this inturn will allow the specific ports to traverse on your network....

    Just a thought...

    terry


     
  13. CurnZ

    CurnZ zero rwkw

    http://en.wikipedia.org/wiki/Snort_%28software%29

    wiki is your friend.

     

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